2k-3k(k-1)=15-4k

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Solution for 2k-3k(k-1)=15-4k equation: 



2k-3k(k-1)=15-4k

We move all terms to the left:

2k-3k(k-1)-(15-4k)=0

We add all the numbers together, and all the variables

2k-3k(k-1)-(-4k+15)=0

We multiply parentheses

-3k^2+2k+3k-(-4k+15)=0

We get rid of parentheses

-3k^2+2k+3k+4k-15=0

We add all the numbers together, and all the variables

-3k^2+9k-15=0

a = -3; b = 9; c = -15;
Δ = b2-4ac
Δ = 92-4·(-3)·(-15)
Δ = -99
Delta is less than zero, so there is no solution for the equation

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