2k-3/k=4/3

Solution for 2k-3/k=4/3 equation:

D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

2*k-(3/k) = 4/3 // - 4/3

2*k-(3/k)-(4/3) = 0

2*k-3*k^-1-4/3 = 0

2*k^1-3*k^-1-4/3*k^0 = 0

(2*k^2-4/3*k^1-3*k^0)/(k^1) = 0 // * k^2

k^1*(2*k^2-4/3*k^1-3*k^0) = 0

k^1

2*k^2+(-4/3)*k-3 = 0

2*k^2+(-4/3)*k-3 = 0

DELTA = (-4/3)^2-(-3*2*4)

DELTA = 232/9

DELTA > 0

k = ((232/9)^(1/2)-(-4/3))/(2*2) or k = (-(-4/3)-(232/9)^(1/2))/(2*2)

k = ((232/9)^(1/2)+4/3)/4 or k = (4/3-(232/9)^(1/2))/4

k in { (4/3-(232/9)^(1/2))/4, ((232/9)^(1/2)+4/3)/4} 

k in { (4/3-(232/9)^(1/2))/4, ((232/9)^(1/2)+4/3)/4 }