2k-3(4-2k)=2(k-3)+2

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Solution for 2k-3(4-2k)=2(k-3)+2 equation: 



2k-3(4-2k)=2(k-3)+2

We move all terms to the left:

2k-3(4-2k)-(2(k-3)+2)=0

We add all the numbers together, and all the variables

2k-3(-2k+4)-(2(k-3)+2)=0

We multiply parentheses

2k+6k-(2(k-3)+2)-12=0



We calculate terms in parentheses: -(2(k-3)+2), so:

2(k-3)+2

We multiply parentheses

2k-6+2

We add all the numbers together, and all the variables

2k-4

Back to the equation:

-(2k-4)



We add all the numbers together, and all the variables

8k-(2k-4)-12=0

We get rid of parentheses

8k-2k+4-12=0

We add all the numbers together, and all the variables

6k-8=0

We move all terms containing k to the left, all other terms to the right

6k=8

k=8/6

k=1+1/3

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