2k-(k+4)=1(k+2)

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Solution for 2k-(k+4)=1(k+2) equation:


Simplifying
2k + -1(k + 4) = 1(k + 2)

Reorder the terms:
2k + -1(4 + k) = 1(k + 2)
2k + (4 * -1 + k * -1) = 1(k + 2)
2k + (-4 + -1k) = 1(k + 2)

Reorder the terms:
-4 + 2k + -1k = 1(k + 2)

Combine like terms: 2k + -1k = 1k
-4 + 1k = 1(k + 2)

Reorder the terms:
-4 + 1k = 1(2 + k)
-4 + 1k = (2 * 1 + k * 1)
-4 + 1k = (2 + 1k)

Add '-1k' to each side of the equation.
-4 + 1k + -1k = 2 + 1k + -1k

Combine like terms: 1k + -1k = 0
-4 + 0 = 2 + 1k + -1k
-4 = 2 + 1k + -1k

Combine like terms: 1k + -1k = 0
-4 = 2 + 0
-4 = 2

Solving
-4 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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