2k-(4k+12)+4=2(k+8)

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Solution for 2k-(4k+12)+4=2(k+8) equation: 



2k-(4k+12)+4=2(k+8)

We move all terms to the left:

2k-(4k+12)+4-(2(k+8))=0

We get rid of parentheses

2k-4k-(2(k+8))-12+4=0



We calculate terms in parentheses: -(2(k+8)), so:

2(k+8)

We multiply parentheses

2k+16

Back to the equation:

-(2k+16)



We add all the numbers together, and all the variables

-2k-(2k+16)-8=0

We get rid of parentheses

-2k-2k-16-8=0

We add all the numbers together, and all the variables

-4k-24=0

We move all terms containing k to the left, all other terms to the right

-4k=24

k=24/-4

k=-6

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