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2k-(-3)=5
We move all terms to the left:
2k-(-3)-(5)=0
determiningTheFunctionDomain 2k-5-(-3)=0
We add all the numbers together, and all the variables
2k-2=0
We move all terms containing k to the left, all other terms to the right
2k=2
k=2/2
k=1
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