2k+5(3k-2)=-95

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Solution for 2k+5(3k-2)=-95 equation: 



2k+5(3k-2)=-95

We move all terms to the left:

2k+5(3k-2)-(-95)=0

We add all the numbers together, and all the variables

2k+5(3k-2)+95=0

We multiply parentheses

2k+15k-10+95=0

We add all the numbers together, and all the variables

17k+85=0

We move all terms containing k to the left, all other terms to the right

17k=-85

k=-85/17

k=-5

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