2k+2(4+k)=3k+4

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Solution for 2k+2(4+k)=3k+4 equation: 



2k+2(4+k)=3k+4

We move all terms to the left:

2k+2(4+k)-(3k+4)=0

We add all the numbers together, and all the variables

2k+2(k+4)-(3k+4)=0

We multiply parentheses

2k+2k-(3k+4)+8=0

We get rid of parentheses

2k+2k-3k-4+8=0

We add all the numbers together, and all the variables

k+4=0

We move all terms containing k to the left, all other terms to the right

k=-4

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