2h2-5h-12=10

Solution for 2h2-5h-12=10 equation:

2h^2-5h-12=10

We move all terms to the left:

2h^2-5h-12-(10)=0

We add all the numbers together, and all the variables

2h^2-5h-22=0

a = 2; b = -5; c = -22;
Δ = b2-4ac
Δ = -52-4·2·(-22)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{201}}{2*2}=\frac{5-\sqrt{201}}{4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{201}}{2*2}=\frac{5+\sqrt{201}}{4}
$