2h-4(h-5)=40

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Solution for 2h-4(h-5)=40 equation: 



2h-4(h-5)=40

We move all terms to the left:

2h-4(h-5)-(40)=0

We multiply parentheses

2h-4h+20-40=0

We add all the numbers together, and all the variables

-2h-20=0

We move all terms containing h to the left, all other terms to the right

-2h=20

h=20/-2

h=-10

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