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2h+2=3(h+1/2)
We move all terms to the left:
2h+2-(3(h+1/2))=0
We add all the numbers together, and all the variables
2h-(3(+h+1/2))+2=0
We multiply all the terms by the denominator
2h*2))-(3(+h+1+2*2))=0
We add all the numbers together, and all the variables
2h*2))-(3(h+5))=0
We add all the numbers together, and all the variables
2h*2))-(3(h=0
Wy multiply elements
4h^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$h=\frac{-b}{2a}=\frac{0}{8}=0$
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