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2g-2=2(g-3)+2
We move all terms to the left:
2g-2-(2(g-3)+2)=0
We calculate terms in parentheses: -(2(g-3)+2), so:We get rid of parentheses
2(g-3)+2
We multiply parentheses
2g-6+2
We add all the numbers together, and all the variables
2g-4
Back to the equation:
-(2g-4)
2g-2g+4-2=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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