2d+9=6(1/3d+1

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Solution for 2d+9=6(1/3d+1 equation: 



2d+9=6(1/3d+1

We move all terms to the left:

2d+9-(6(1/3d+1)=0



Domain of the equation: 3d+1)+9!=0

d∈R



We multiply all the terms by the denominator


2d*3d+1)+9-(6(1=0

We add all the numbers together, and all the variables

2d*3d=0

Wy multiply elements

6d^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{12}=0$

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