2d+1/4=(1/2d+1)

Solution for 2d+1/4=(1/2d+1) equation:

2d+1/4=(1/2d+1)

We move all terms to the left:

2d+1/4-((1/2d+1))=0


Domain of the equation: 2d+1))!=0

d∈R


We calculate fractions


2d+()/2d+2d/2d=0

Fractions to decimals

()/2d+2d+1=0

We multiply all the terms by the denominator


2d*2d+1*2d+()=0

We add all the numbers together, and all the variables

2d*2d+1*2d=0

Wy multiply elements

4d^2+2d=0

a = 4; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·4·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*4}=\frac{-4}{8}
=-1/2
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*4}=\frac{0}{8}
=0
$