2d+(1/6)=6(1/3d+1)

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Solution for 2d+(1/6)=6(1/3d+1) equation: 


d in (-oo:+oo)

2*d+1/6 = 6*((1/3)*d+1) // - 6*((1/3)*d+1)

2*d-(6*((1/3)*d+1))+1/6 = 0

2*d-6*((1/3)*d+1)+1/6 = 0

2*d-6*(1/3*d+1)+1/6 = 0

(-6*6*(1/3*d+1))/6+(2*6*d)/6+1/6 = 0

2*6*d-6*6*(1/3*d+1)+1 = 0

1-36 = 0

-35 = 0

-35/6 = 0

-35/6 = 0 // * 6

-35 = 0

d belongs to the empty set

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