2d(5d+8)=0

Solution for 2d(5d+8)=0 equation:

2d(5d+8)=0

We multiply parentheses

10d^2+16d=0

a = 10; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·10·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*10}=\frac{-32}{20}
=-1+3/5
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*10}=\frac{0}{20}
=0
$