2cos(pi/4x)

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Solution for 2cos(pi/4x) equation: 


x in (-oo:+oo)

2*cos((pi/4)*x) = 0

cos((pi/4)*x) = 0

cos((pi/4)*x) = 0  <=>  (pi/4)*x = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

(pi/4)*x-t_1 = 0

(pi/4)*x-t_1 = 0 // + t_1

(pi/4)*x = t_1 // : pi/4

x = t_1/(pi/4)

x = pi*k_1+pi/2/(pi/4) i k_1 należy do I

2*cos((pi/4)*x) = 0  <=>  2 = 0 or 2*cos((pi/4)*x) = 0  <=>  cos((pi/4)*x) = 0

x = pi*k_1+pi/2/(pi/4)

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