2cos(2x)+sin(x)=2

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Solution for 2cos(2x)+sin(x)=2 equation:


Simplifying
2cos(2x) + sin(x) = 2

Remove parenthesis around (2x)
2cos * 2x + sin(x) = 2

Reorder the terms for easier multiplication:
2 * 2cos * x + sin(x) = 2

Multiply 2 * 2
4cos * x + sin(x) = 2

Multiply cos * x
4cosx + sin(x) = 2

Multiply ins * x
4cosx + insx = 2

Solving
4cosx + insx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1insx' to each side of the equation.
4cosx + insx + -1insx = 2 + -1insx

Combine like terms: insx + -1insx = 0
4cosx + 0 = 2 + -1insx
4cosx = 2 + -1insx

Divide each side by '4osx'.
c = 0.5o-1s-1x-1 + -0.25ino-1

Simplifying
c = 0.5o-1s-1x-1 + -0.25ino-1

Reorder the terms:
c = -0.25ino-1 + 0.5o-1s-1x-1

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