2cos(2x)+5sin(x)-3=0

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Solution for 2cos(2x)+5sin(x)-3=0 equation:


Simplifying
2cos(2x) + 5sin(x) + -3 = 0

Remove parenthesis around (2x)
2cos * 2x + 5sin(x) + -3 = 0

Reorder the terms for easier multiplication:
2 * 2cos * x + 5sin(x) + -3 = 0

Multiply 2 * 2
4cos * x + 5sin(x) + -3 = 0

Multiply cos * x
4cosx + 5sin(x) + -3 = 0

Multiply ins * x
4cosx + 5insx + -3 = 0

Reorder the terms:
-3 + 4cosx + 5insx = 0

Solving
-3 + 4cosx + 5insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 4cosx + 3 + 5insx = 0 + 3

Reorder the terms:
-3 + 3 + 4cosx + 5insx = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 4cosx + 5insx = 0 + 3
4cosx + 5insx = 0 + 3

Combine like terms: 0 + 3 = 3
4cosx + 5insx = 3

Add '-5insx' to each side of the equation.
4cosx + 5insx + -5insx = 3 + -5insx

Combine like terms: 5insx + -5insx = 0
4cosx + 0 = 3 + -5insx
4cosx = 3 + -5insx

Divide each side by '4osx'.
c = 0.75o-1s-1x-1 + -1.25ino-1

Simplifying
c = 0.75o-1s-1x-1 + -1.25ino-1

Reorder the terms:
c = -1.25ino-1 + 0.75o-1s-1x-1

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