2cos(2x)+4cos(x)-1=0

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Solution for 2cos(2x)+4cos(x)-1=0 equation:


Simplifying
2cos(2x) + 4cos(x) + -1 = 0

Remove parenthesis around (2x)
2cos * 2x + 4cos(x) + -1 = 0

Reorder the terms for easier multiplication:
2 * 2cos * x + 4cos(x) + -1 = 0

Multiply 2 * 2
4cos * x + 4cos(x) + -1 = 0

Multiply cos * x
4cosx + 4cos(x) + -1 = 0

Multiply cos * x
4cosx + 4cosx + -1 = 0

Reorder the terms:
-1 + 4cosx + 4cosx = 0

Combine like terms: 4cosx + 4cosx = 8cosx
-1 + 8cosx = 0

Solving
-1 + 8cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 8cosx = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 8cosx = 0 + 1
8cosx = 0 + 1

Combine like terms: 0 + 1 = 1
8cosx = 1

Divide each side by '8osx'.
c = 0.125o-1s-1x-1

Simplifying
c = 0.125o-1s-1x-1

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