2c-3=29(6-c)+7c

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Solution for 2c-3=29(6-c)+7c equation: 



2c-3=29(6-c)+7c

We move all terms to the left:

2c-3-(29(6-c)+7c)=0

We add all the numbers together, and all the variables

2c-(29(-1c+6)+7c)-3=0



We calculate terms in parentheses: -(29(-1c+6)+7c), so:

29(-1c+6)+7c

We add all the numbers together, and all the variables

7c+29(-1c+6)

We multiply parentheses

7c-29c+174

We add all the numbers together, and all the variables

-22c+174

Back to the equation:

-(-22c+174)



We get rid of parentheses

2c+22c-174-3=0

We add all the numbers together, and all the variables

24c-177=0

We move all terms containing c to the left, all other terms to the right

24c=177

c=177/24

c=7+3/8

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