2c-3=2(6-c)-12c

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Solution for 2c-3=2(6-c)-12c equation:



2c-3=2(6-c)-12c
We move all terms to the left:
2c-3-(2(6-c)-12c)=0
We add all the numbers together, and all the variables
2c-(2(-1c+6)-12c)-3=0
We calculate terms in parentheses: -(2(-1c+6)-12c), so:
2(-1c+6)-12c
We add all the numbers together, and all the variables
-12c+2(-1c+6)
We multiply parentheses
-12c-2c+12
We add all the numbers together, and all the variables
-14c+12
Back to the equation:
-(-14c+12)
We get rid of parentheses
2c+14c-12-3=0
We add all the numbers together, and all the variables
16c-15=0
We move all terms containing c to the left, all other terms to the right
16c=15
c=15/16
c=15/16

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