2c-3=(6-c)+7C

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Solution for 2c-3=(6-c)+7C equation: 



2c-3=(6-c)+7

We move all terms to the left:

2c-3-((6-c)+7)=0

We add all the numbers together, and all the variables

2c-((-1c+6)+7)-3=0



We calculate terms in parentheses: -((-1c+6)+7), so:

(-1c+6)+7

We get rid of parentheses

-1c+6+7

We add all the numbers together, and all the variables

-1c+13

Back to the equation:

-(-1c+13)



We get rid of parentheses

2c+1c-13-3=0

We add all the numbers together, and all the variables

3c-16=0

We move all terms containing c to the left, all other terms to the right

3c=16

c=16/3

c=5+1/3

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