2c-2=(c-1)-(1-c)

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Solution for 2c-2=(c-1)-(1-c) equation:


Simplifying
2c + -2 = (c + -1) + -1(1 + -1c)

Reorder the terms:
-2 + 2c = (c + -1) + -1(1 + -1c)

Reorder the terms:
-2 + 2c = (-1 + c) + -1(1 + -1c)

Remove parenthesis around (-1 + c)
-2 + 2c = -1 + c + -1(1 + -1c)
-2 + 2c = -1 + c + (1 * -1 + -1c * -1)
-2 + 2c = -1 + c + (-1 + 1c)

Reorder the terms:
-2 + 2c = -1 + -1 + c + 1c

Combine like terms: -1 + -1 = -2
-2 + 2c = -2 + c + 1c

Combine like terms: c + 1c = 2c
-2 + 2c = -2 + 2c

Add '2' to each side of the equation.
-2 + 2 + 2c = -2 + 2 + 2c

Combine like terms: -2 + 2 = 0
0 + 2c = -2 + 2 + 2c
2c = -2 + 2 + 2c

Combine like terms: -2 + 2 = 0
2c = 0 + 2c
2c = 2c

Add '-2c' to each side of the equation.
2c + -2c = 2c + -2c

Combine like terms: 2c + -2c = 0
0 = 2c + -2c

Combine like terms: 2c + -2c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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