2c-11+3-5=6-8c+17

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Solution for 2c-11+3-5=6-8c+17 equation: 



2c-11+3-5=6-8c+17

We move all terms to the left:

2c-11+3-5-(6-8c+17)=0

We add all the numbers together, and all the variables

2c-(-8c+23)-11+3-5=0

We add all the numbers together, and all the variables

2c-(-8c+23)-13=0

We get rid of parentheses

2c+8c-23-13=0

We add all the numbers together, and all the variables

10c-36=0

We move all terms containing c to the left, all other terms to the right

10c=36

c=36/10

c=3+3/5

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