2c-(c+5)=4(c-2)

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Solution for 2c-(c+5)=4(c-2) equation:


Simplifying
2c + -1(c + 5) = 4(c + -2)

Reorder the terms:
2c + -1(5 + c) = 4(c + -2)
2c + (5 * -1 + c * -1) = 4(c + -2)
2c + (-5 + -1c) = 4(c + -2)

Reorder the terms:
-5 + 2c + -1c = 4(c + -2)

Combine like terms: 2c + -1c = 1c
-5 + 1c = 4(c + -2)

Reorder the terms:
-5 + 1c = 4(-2 + c)
-5 + 1c = (-2 * 4 + c * 4)
-5 + 1c = (-8 + 4c)

Solving
-5 + 1c = -8 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-5 + 1c + -4c = -8 + 4c + -4c

Combine like terms: 1c + -4c = -3c
-5 + -3c = -8 + 4c + -4c

Combine like terms: 4c + -4c = 0
-5 + -3c = -8 + 0
-5 + -3c = -8

Add '5' to each side of the equation.
-5 + 5 + -3c = -8 + 5

Combine like terms: -5 + 5 = 0
0 + -3c = -8 + 5
-3c = -8 + 5

Combine like terms: -8 + 5 = -3
-3c = -3

Divide each side by '-3'.
c = 1

Simplifying
c = 1

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