2c+10+5c-3=7(c+1)

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Solution for 2c+10+5c-3=7(c+1) equation: 


Simplifying
2c + 10 + 5c + -3 = 7(c + 1)

Reorder the terms:
10 + -3 + 2c + 5c = 7(c + 1)

Combine like terms: 10 + -3 = 7
7 + 2c + 5c = 7(c + 1)

Combine like terms: 2c + 5c = 7c
7 + 7c = 7(c + 1)

Reorder the terms:
7 + 7c = 7(1 + c)
7 + 7c = (1 * 7 + c * 7)
7 + 7c = (7 + 7c)

Add '-7' to each side of the equation.
7 + -7 + 7c = 7 + -7 + 7c

Combine like terms: 7 + -7 = 0
0 + 7c = 7 + -7 + 7c
7c = 7 + -7 + 7c

Combine like terms: 7 + -7 = 0
7c = 0 + 7c
7c = 7c

Add '-7c' to each side of the equation.
7c + -7c = 7c + -7c

Combine like terms: 7c + -7c = 0
0 = 7c + -7c

Combine like terms: 7c + -7c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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