2c+10+(21+9)3=120

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Solution for 2c+10+(21+9)3=120 equation: 



2c+10+(21+9)3=120

We move all terms to the left:

2c+10+(21+9)3-(120)=0

determiningTheFunctionDomain
2c+10-120+(21+9)3=0

We add all the numbers together, and all the variables

2c+10-120+303=0

We add all the numbers together, and all the variables

2c+193=0

We move all terms containing c to the left, all other terms to the right

2c=-193

c=-193/2

c=-96+1/2

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