2c+(3c+-4)=4c+-4

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Solution for 2c+(3c+-4)=4c+-4 equation:


Simplifying
2c + (3c + -4) = 4c + -4

Reorder the terms:
2c + (-4 + 3c) = 4c + -4

Remove parenthesis around (-4 + 3c)
2c + -4 + 3c = 4c + -4

Reorder the terms:
-4 + 2c + 3c = 4c + -4

Combine like terms: 2c + 3c = 5c
-4 + 5c = 4c + -4

Reorder the terms:
-4 + 5c = -4 + 4c

Add '4' to each side of the equation.
-4 + 4 + 5c = -4 + 4 + 4c

Combine like terms: -4 + 4 = 0
0 + 5c = -4 + 4 + 4c
5c = -4 + 4 + 4c

Combine like terms: -4 + 4 = 0
5c = 0 + 4c
5c = 4c

Solving
5c = 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
5c + -4c = 4c + -4c

Combine like terms: 5c + -4c = 1c
1c = 4c + -4c

Combine like terms: 4c + -4c = 0
1c = 0

Divide each side by '1'.
c = 0

Simplifying
c = 0

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