2c(c+6)=4(c-2)

Solution for 2c(c+6)=4(c-2) equation:

2c(c+6)=4(c-2)

We move all terms to the left:

2c(c+6)-(4(c-2))=0

We multiply parentheses

2c^2+12c-(4(c-2))=0


We calculate terms in parentheses: -(4(c-2)), so:

4(c-2)

We multiply parentheses

4c-8

Back to the equation:

-(4c-8)


We get rid of parentheses

2c^2+12c-4c+8=0

We add all the numbers together, and all the variables

2c^2+8c+8=0

a = 2; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·2·8
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{-8}{4}=-2$