2c(3c-4)=-4c-5

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Solution for 2c(3c-4)=-4c-5 equation: 



2c(3c-4)=-4c-5

We move all terms to the left:

2c(3c-4)-(-4c-5)=0

We multiply parentheses

6c^2-8c-(-4c-5)=0

We get rid of parentheses

6c^2-8c+4c+5=0

We add all the numbers together, and all the variables

6c^2-4c+5=0

a = 6; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·6·5
Δ = -104
Delta is less than zero, so there is no solution for the equation

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