2b=3(b-7)=44

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Solution for 2b=3(b-7)=44 equation: 



2b=3(b-7)=44

We move all terms to the left:

2b-(3(b-7))=0



We calculate terms in parentheses: -(3(b-7)), so:

3(b-7)

We multiply parentheses

3b-21

Back to the equation:

-(3b-21)



We get rid of parentheses

2b-3b+21=0

We add all the numbers together, and all the variables

-1b+21=0

We move all terms containing b to the left, all other terms to the right

-b=-21

b=-21/-1

b=+21

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