2b2=1,152

Solution for 2b2=1,152 equation:

2b^2=1.152

We move all terms to the left:

2b^2-(1.152)=0

We add all the numbers together, and all the variables

2b^2-1.152=0

a = 2; b = 0; c = -1.152;
Δ = b2-4ac
Δ = 02-4·2·(-1.152)
Δ = 9.216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{9.216}}{2*2}=\frac{0-\sqrt{9.216}}{4}
=-\frac{\sqrt{}}{4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{9.216}}{2*2}=\frac{0+\sqrt{9.216}}{4}
=\frac{\sqrt{}}{4}
$