2b/5b-1b/4b=3

Solution for 2b/5b-1b/4b=3 equation:

2b/5b-1b/4b=3

We move all terms to the left:

2b/5b-1b/4b-(3)=0


Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



Domain of the equation: 4b!=0

b!=0/4

b!=0

b∈R


We calculate fractions


(-5b^2)/20b^2+8b^2/20b^2-3=0

We multiply all the terms by the denominator


(-5b^2)+8b^2-3*20b^2=0

We add all the numbers together, and all the variables

8b^2+(-5b^2)-3*20b^2=0

Wy multiply elements

8b^2+(-5b^2)-60b^2=0

We get rid of parentheses

8b^2-5b^2-60b^2=0

We add all the numbers together, and all the variables

-57b^2=0

a = -57; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-57)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-114}=0$