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2b-2=16+2(b-15)
We move all terms to the left:
2b-2-(16+2(b-15))=0
We calculate terms in parentheses: -(16+2(b-15)), so:We get rid of parentheses
16+2(b-15)
determiningTheFunctionDomain 2(b-15)+16
We multiply parentheses
2b-30+16
We add all the numbers together, and all the variables
2b-14
Back to the equation:
-(2b-14)
2b-2b+14-2=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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