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2b-((2b+2)+3b)=b-(3b+6)-(2b-10)
We move all terms to the left:
2b-((2b+2)+3b)-(b-(3b+6)-(2b-10))=0
We calculate terms in parentheses: -((2b+2)+3b), so:
(2b+2)+3b
We add all the numbers together, and all the variables
3b+(2b+2)
We get rid of parentheses
3b+2b+2
We add all the numbers together, and all the variables
5b+2
Back to the equation:
-(5b+2)
We calculate terms in parentheses: -(b-(3b+6)-(2b-10)), so:We get rid of parentheses
b-(3b+6)-(2b-10)
We get rid of parentheses
b-3b-2b-6+10
We add all the numbers together, and all the variables
-4b+4
Back to the equation:
-(-4b+4)
2b-5b+4b-2-4=0
We add all the numbers together, and all the variables
b-6=0
We move all terms containing b to the left, all other terms to the right
b=6
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