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2b+7/2b=-11
We move all terms to the left:
2b+7/2b-(-11)=0
Domain of the equation: 2b!=0We add all the numbers together, and all the variables
b!=0/2
b!=0
b∈R
2b+7/2b+11=0
We multiply all the terms by the denominator
2b*2b+11*2b+7=0
Wy multiply elements
4b^2+22b+7=0
a = 4; b = 22; c = +7;
Δ = b2-4ac
Δ = 222-4·4·7
Δ = 372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{372}=\sqrt{4*93}=\sqrt{4}*\sqrt{93}=2\sqrt{93}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{93}}{2*4}=\frac{-22-2\sqrt{93}}{8} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{93}}{2*4}=\frac{-22+2\sqrt{93}}{8} $
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