2b+3(b-2)=29

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Solution for 2b+3(b-2)=29 equation: 



2b+3(b-2)=29

We move all terms to the left:

2b+3(b-2)-(29)=0

We multiply parentheses

2b+3b-6-29=0

We add all the numbers together, and all the variables

5b-35=0

We move all terms containing b to the left, all other terms to the right

5b=35

b=35/5

b=7

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