2a-1=4(a+1)+7a+6

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Solution for 2a-1=4(a+1)+7a+6 equation: 



2a-1=4(a+1)+7a+6

We move all terms to the left:

2a-1-(4(a+1)+7a+6)=0



We calculate terms in parentheses: -(4(a+1)+7a+6), so:

4(a+1)+7a+6

We add all the numbers together, and all the variables

7a+4(a+1)+6

We multiply parentheses

7a+4a+4+6

We add all the numbers together, and all the variables

11a+10

Back to the equation:

-(11a+10)



We get rid of parentheses

2a-11a-10-1=0

We add all the numbers together, and all the variables

-9a-11=0

We move all terms containing a to the left, all other terms to the right

-9a=11

a=11/-9

a=-1+2/9

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