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2a+9=1+3(2+a)
We move all terms to the left:
2a+9-(1+3(2+a))=0
We add all the numbers together, and all the variables
2a-(1+3(a+2))+9=0
We calculate terms in parentheses: -(1+3(a+2)), so:We get rid of parentheses
1+3(a+2)
determiningTheFunctionDomain 3(a+2)+1
We multiply parentheses
3a+6+1
We add all the numbers together, and all the variables
3a+7
Back to the equation:
-(3a+7)
2a-3a-7+9=0
We add all the numbers together, and all the variables
-1a+2=0
We move all terms containing a to the left, all other terms to the right
-a=-2
a=-2/-1
a=+2
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