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2a+6a(2)=180
We move all terms to the left:
2a+6a(2)-(180)=0
We add all the numbers together, and all the variables
6a^2+2a-180=0
a = 6; b = 2; c = -180;
Δ = b2-4ac
Δ = 22-4·6·(-180)
Δ = 4324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4324}=\sqrt{4*1081}=\sqrt{4}*\sqrt{1081}=2\sqrt{1081}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1081}}{2*6}=\frac{-2-2\sqrt{1081}}{12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1081}}{2*6}=\frac{-2+2\sqrt{1081}}{12} $
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