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2a(5/a)=11
We move all terms to the left:
2a(5/a)-(11)=0
Domain of the equation: a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
2a(+5/a)-11=0
We multiply parentheses
10a^2-11=0
a = 10; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·10·(-11)
Δ = 440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{440}=\sqrt{4*110}=\sqrt{4}*\sqrt{110}=2\sqrt{110}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{110}}{2*10}=\frac{0-2\sqrt{110}}{20} =-\frac{2\sqrt{110}}{20} =-\frac{\sqrt{110}}{10} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{110}}{2*10}=\frac{0+2\sqrt{110}}{20} =\frac{2\sqrt{110}}{20} =\frac{\sqrt{110}}{10} $
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