2B+(D+3)+D=4+3B

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Solution for 2B+(D+3)+D=4+3B equation:


Simplifying
2B + (D + 3) + D = 4 + 3B

Reorder the terms:
2B + (3 + D) + D = 4 + 3B

Remove parenthesis around (3 + D)
2B + 3 + D + D = 4 + 3B

Reorder the terms:
3 + 2B + D + D = 4 + 3B

Combine like terms: D + D = 2D
3 + 2B + 2D = 4 + 3B

Solving
3 + 2B + 2D = 4 + 3B

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-3B' to each side of the equation.
3 + 2B + -3B + 2D = 4 + 3B + -3B

Combine like terms: 2B + -3B = -1B
3 + -1B + 2D = 4 + 3B + -3B

Combine like terms: 3B + -3B = 0
3 + -1B + 2D = 4 + 0
3 + -1B + 2D = 4

Add '-3' to each side of the equation.
3 + -1B + -3 + 2D = 4 + -3

Reorder the terms:
3 + -3 + -1B + 2D = 4 + -3

Combine like terms: 3 + -3 = 0
0 + -1B + 2D = 4 + -3
-1B + 2D = 4 + -3

Combine like terms: 4 + -3 = 1
-1B + 2D = 1

Add '-2D' to each side of the equation.
-1B + 2D + -2D = 1 + -2D

Combine like terms: 2D + -2D = 0
-1B + 0 = 1 + -2D
-1B = 1 + -2D

Divide each side by '-1'.
B = -1 + 2D

Simplifying
B = -1 + 2D

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