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2=y(52-3y)
We move all terms to the left:
2-(y(52-3y))=0
We add all the numbers together, and all the variables
-(y(-3y+52))+2=0
We calculate terms in parentheses: -(y(-3y+52)), so:We get rid of parentheses
y(-3y+52)
We multiply parentheses
-3y^2+52y
Back to the equation:
-(-3y^2+52y)
3y^2-52y+2=0
a = 3; b = -52; c = +2;
Δ = b2-4ac
Δ = -522-4·3·2
Δ = 2680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2680}=\sqrt{4*670}=\sqrt{4}*\sqrt{670}=2\sqrt{670}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-2\sqrt{670}}{2*3}=\frac{52-2\sqrt{670}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+2\sqrt{670}}{2*3}=\frac{52+2\sqrt{670}}{6} $
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