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2=a2-1
We move all terms to the left:
2-(a2-1)=0
We add all the numbers together, and all the variables
-(+a^2-1)+2=0
We get rid of parentheses
-a^2+1+2=0
We add all the numbers together, and all the variables
-1a^2+3=0
a = -1; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-1)·3
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{3}}{2*-1}=\frac{0-2\sqrt{3}}{-2} =-\frac{2\sqrt{3}}{-2} =-\frac{\sqrt{3}}{-1} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{3}}{2*-1}=\frac{0+2\sqrt{3}}{-2} =\frac{2\sqrt{3}}{-2} =\frac{\sqrt{3}}{-1} $
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