2=8+(4-x)-2

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Solution for 2=8+(4-x)-2 equation: 



2=8+(4-x)-2

We move all terms to the left:

2-(8+(4-x)-2)=0

We add all the numbers together, and all the variables

-(8+(-1x+4)-2)+2=0



We calculate terms in parentheses: -(8+(-1x+4)-2), so:

8+(-1x+4)-2

determiningTheFunctionDomain
(-1x+4)+8-2

We add all the numbers together, and all the variables

(-1x+4)+6

We get rid of parentheses

-1x+4+6

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We get rid of parentheses

1x-10+2=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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