2=47/5x

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Solution for 2=47/5x equation: 



2=47/5x

We move all terms to the left:

2-(47/5x)=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(+47/5x)+2=0

We get rid of parentheses

-47/5x+2=0

We multiply all the terms by the denominator


2*5x-47=0

Wy multiply elements

10x-47=0

We move all terms containing x to the left, all other terms to the right

10x=47

x=47/10

x=4+7/10

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