2=4(6-x)+42

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Solution for 2=4(6-x)+42 equation: 



2=4(6-x)+42

We move all terms to the left:

2-(4(6-x)+42)=0

We add all the numbers together, and all the variables

-(4(-1x+6)+42)+2=0



We calculate terms in parentheses: -(4(-1x+6)+42), so:

4(-1x+6)+42

We multiply parentheses

-4x+24+42

We add all the numbers together, and all the variables

-4x+66

Back to the equation:

-(-4x+66)



We get rid of parentheses

4x-66+2=0

We add all the numbers together, and all the variables

4x-64=0

We move all terms containing x to the left, all other terms to the right

4x=64

x=64/4

x=16

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