2=3(z-11)-10

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Solution for 2=3(z-11)-10 equation: 



2=3(z-11)-10

We move all terms to the left:

2-(3(z-11)-10)=0



We calculate terms in parentheses: -(3(z-11)-10), so:

3(z-11)-10

We multiply parentheses

3z-33-10

We add all the numbers together, and all the variables

3z-43

Back to the equation:

-(3z-43)



We get rid of parentheses

-3z+43+2=0

We add all the numbers together, and all the variables

-3z+45=0

We move all terms containing z to the left, all other terms to the right

-3z=-45

z=-45/-3

z=+15

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