2=3(1-2z)+3z

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Solution for 2=3(1-2z)+3z equation:



2=3(1-2z)+3z
We move all terms to the left:
2-(3(1-2z)+3z)=0
We add all the numbers together, and all the variables
-(3(-2z+1)+3z)+2=0
We calculate terms in parentheses: -(3(-2z+1)+3z), so:
3(-2z+1)+3z
We add all the numbers together, and all the variables
3z+3(-2z+1)
We multiply parentheses
3z-6z+3
We add all the numbers together, and all the variables
-3z+3
Back to the equation:
-(-3z+3)
We get rid of parentheses
3z-3+2=0
We add all the numbers together, and all the variables
3z-1=0
We move all terms containing z to the left, all other terms to the right
3z=1
z=1/3
z=1/3

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